问 HN:一个关于量纲分析的无聊游戏

1作者: egoism7 个月前
几周前,我曾设想过可能存在一个电磁场的维度阶梯,但一直无法将其转化为可用的东西。现在我分享一些我感到沮丧的 Markdown 笔记。<p>从安培的定义开始(N/m,kg/s²)...<p>- V = 电压,单位为伏特,(2019 年前等于 m²/s)<p>- Q = 电荷,单位为库仑,(2019 年前等于 kg/s)<p>*惯性表面(J·s²)*<p><pre><code> ∫V dt × ∫Q dt = m² × kg </code></pre> *作用模式(J·s)*<p><pre><code> V × ∫Q dt = (m²/s) × kg ∫V dt × Q = m² × (kg/s) </code></pre> *能量,应力模式(J)*<p><pre><code> dV/dt × ∫Q dt = (m²/s²) × kg V × Q = (m²/s) × (kg/s) ∫V dt × dQ/dt = m² × (kg/s²) </code></pre> *功率,应力波(J/s)*<p><pre><code> dV/dt × Q = (m²/s²) × (kg/s) V × dQ/dt = (m²/s) × (kg/s²) </code></pre> *冲量,波的转换(J/s²)*<p><pre><code> dV/dt × dQ/dt = (m²/s²) × (kg/s²) </code></pre> *空间导数,对...“物质”的影响?*<p>- d(表面)/dx ~ 传输<p>- d(作用)/dx ~ 动量<p>- d(能量)/dx ~ 力<p>- d(功率)/dx ~ ??? 传播?<p>- d(冲量)/dx ~ ??? 转换?<p>*空间积分,对...“空间”的影响?*<p>- ∫(表面)dx ~ 惯性体积<p>- ∫(作用)dx ~ kgm³/s<p>- ∫(能量)dx ~ kgm³/s²<p>- ∫(功率)dx ~ kgm³/s³<p>- ∫(冲量)dx ~ kgm³/s⁴<p>在功率的波模式中,“相位”= dV/dt,电荷 = Q,使用 Heaviside 的波动方程 `d2(伏特)/dt2 + v2 * d2(电流)/dx2 = d2(电流)/dt2 + v2 * d2(伏特)/dx2` 那么... `d2(相位)/dt2 + u2 * d2(电荷)/dx2 = d2(电荷)/dt2 + u2 * d2(相位)/dx2` 其中 v2 = 1 / LC,u2 = 1 / ??
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I thought a few weeks ago, that there might be a dimensional ladder for EM, but I can&#x27;t figure out how turn into something usable. I&#x27;m sharing some of my markdown notes, now frustrated.<p>Starting from how an Ampere used to be defined (N&#x2F;m, kg&#x2F;s2)...<p>- V = Voltage, in Volts, (pre-2019 equal to m2&#x2F;s)<p>- Q = Charge, in Coulombs, (pre-2019 equal to kg&#x2F;s)<p>*Inertial Surfaces (J·s²)*<p><pre><code> ∫V dt × ∫Q dt = m² × kg </code></pre> *Modes of Action (J·s)*<p><pre><code> V × ∫Q dt = (m²&#x2F;s) × kg ∫V dt × Q = m² × (kg&#x2F;s) </code></pre> *Energy, Patterns of Stress (J)*<p><pre><code> dV&#x2F;dt × ∫Q dt = (m²&#x2F;s²) × kg V × Q = (m²&#x2F;s) × (kg&#x2F;s) ∫V dt × dQ&#x2F;dt = m² × (kg&#x2F;s²) </code></pre> *Power, Waves of Stress (J&#x2F;s)*<p><pre><code> dV&#x2F;dt × Q = (m²&#x2F;s²) × (kg&#x2F;s) V × dQ&#x2F;dt = (m²&#x2F;s) × (kg&#x2F;s²) </code></pre> *Impulse, Wave Conversions (J&#x2F;s²)*<p><pre><code> dV&#x2F;dt × dQ&#x2F;dt = (m²&#x2F;s²) × (kg&#x2F;s²) </code></pre> *Spatial Derivatives, Effects on... &#x27;Matter&#x27;?*<p>- d(Surface)&#x2F;dx ~ Transport<p>- d(Action)&#x2F;dx ~ Momentum<p>- d(Energy)&#x2F;dx ~ Force<p>- d(Power)&#x2F;dx ~ ??? Propagation?<p>- d(Impulse)&#x2F;dx ~ ??? Conversion?<p>*Spatial Integrals, Effects on... &#x27;Space&#x27;?*<p>- ∫(Surface)dx ~ Inertial Volume<p>- ∫(Action)dx ~ kgm3&#x2F;s<p>- ∫(Energy)dx ~ kgm3&#x2F;s2<p>- ∫(Power)dx ~ kgm3&#x2F;s3<p>- ∫(Impulse)dx ~ kgm3&#x2F;s4<p>In the wave modes for Power, &#x27;Phase&#x27; = dV&#x2F;dt, Charge = Q, with Heaviside&#x27;s wave equation `d2(Volts)&#x2F;dt2 + v2 * d2(Current)&#x2F;dx2 = d2(Current)&#x2F;dt2 + v2 * d2(Volts)&#x2F;dx2` would then.... `d2(Phase)&#x2F;dt2 + u2 * d2(Charge)&#x2F;dx2 = d2(Charge)&#x2F;dt2 + u2 * d2(Phase)&#x2F;dx2` where v2 = 1 &#x2F; LC, u2 = 1 &#x2F; ??